Engineering Quantitative Aptitude English Reasoning General Knowledge Coding Others

Quiz: Pie Chart-3

To View Tricks: Login Required

Number of Questions: 5

Question: 1 -

What was the total number of illiterate people in A.P. and M.P. in 1998?

Options:

  1. 876040

  2. 981550

  3. 1161160

  4. 932170

    5. Answer:

    1161160
    Solution:

    No. of illiterate people in A.P. = [ 7 of (25% of 3276000) ] = 637000.
    9
    No. of illiterate people in M.P. = [ 4 of (20% of 3276000) ] = 524160.
    5

    Therefore Total number = (637000 + 524160) = 1161160.

Question: 2 -

What was the number of males in U.P. in the year 1998?

Options:

  1. 254650

  2. 294840

  3. 341200

  4. 321470

    5. Answer:

    294840
    Solution:

    Number of males in U.P.
    = [   3 of (15% of 3276000) ]
    5
     
    = 3 x 15 x 3726000
    5 100
      = 294840.

Question: 3 -

What is the ratio of the number of females in T.N. to the number of females in Delhi?

Options:

  1. 15 : 14

  2. 9 : 7

  3. 13 : 11

  4. 7 : 5

    5. Answer:

    15 : 14
    Solution:

    Required ratio

    =
    4 of (9% of 3276000)
    7
    3 of (8% of 3276000)
    5

     

    =
    ( 4 x 9 )
    7
    ( 3 x 8 )
    5

     

    = ( 4 x 9 x 5 x 1 )
    7 3 8

     

    = 15 .
    14

     

Question: 4 -

If in the year 1998, there was an increase of 10% in the population of U.P. and 12% in the population of M.P. compared to the previous year, then what was the ratio of populations of U.P. and M.P. in 1997?

Options:

  1. 42 : 55

  2. 4 : 5

  3. 7 : 11

  4. 48 : 55

    5. Answer:

    42 : 55
    Solution:

    Let x be the population of U.P. in 1997. Then,

    Population of U.P. in 1998 = 110% of x = 110 x x.
    100

    Also, let y be the population of M.P. in 1997. Then,

    Population of M.P. in 1998 = 112% of y = 112 x y.
    100
    Ratio of populations of U.P. and M.P. in 1998 =
    ( 110 x x )
    100
    		= 110x .
    ( 112 x y )
    100
    		112y
    From the pie-chart, this ratio is 15 .
    20
    Therefore 110x = 15   =>   x = 15 x 112 = 42 .
    112y 20 y 20 110 55

    Thus, ratio of populations of U.P. and M.P. in 1997 = x : y = 42 : 55.

Question: 5 -

Directions to Solve

Study the following graph and the table and answer the questions given below.

Data of different states regarding population of states in the year 1998

Total population of the given States = 3276000.

States Sex and Literacy wise Population Ratio
Sex Literacy
M F Literate Illiterate
A.P 5 3 2 7
M.P 3 1 1 4
Delhi 2 3 2 1
Goa 3 5 3 2
Bihar 3 4 4 1
U.P. 3 2 7 2
T.N. 3 4 9 4

Q: What will be the percentage of total number of males in U.P., M.P. and Goa together to the total population of all the given states?

Options:

  1. 25%

  2. 31.5%

  3. 28.5%

  4. 27.5%
    5. Answer:

    28.5%
    Solution:

    Number of males in U.P = [ 3 of (15% of N) ]   = 3 x 15 x N   = 9 x N .
    5 5 100 100

    where N = 3276000.

    Number of males in M.P = [ 3 of (20% of N) ]   = 3 x 20 x N   = 15 x N .
    4 4 100 100
    Number of males in Goa = [ 3 of (12% of N) ]   = 3 x 12 x N   = 4.5 x N .
    8 8 100 100
    Therefore Total number of males in these three states
    = (9 + 15 + 4.5) x N
    100
     
    = ( 28.5 x N ) .
    100
    Therefore Required Percentage = [
    ( 28.5 x N )
    100
    		x 100 ] % = 28.5%.
    N